把下列各式分解因式1x5x2a2x1b

2021-03-19 18:34:12 字數 1796 閱讀 5686

1樓:手機使用者

(1)x5-x

=x(x4-1)

=x(x2+1)(

x2-1)

x(x2+1)(x+1)(x-1);

(2)a2(x-1)+b2(1-x)

=a2(x-1)-b2(x-1)

(x-1)(a2-b2)

=(x-1)(a+b)(a-b);

(3)(a-b)2+18(a-b)+81

=[(a-b)+9]2=(a-b+9)2;

(4)(x2+2x)2+2x2+4x+1

=(x2+2x)2+2(x2+2x)+1

=[(x2+2x)+1]2

=(x2+2x+1)2

=[(x+1)2]2

=(x+1)4

把下列各式因式分解:(1)ax2-16ay2(2)-2a3+12a2-18a(3)a2-2ab+b2-1(4)a2(x-y)-4b2(x-y)(5)

2樓:小米米米小米米

(1)ax2-16ay2=a(x+4y)(

duzhix-4y);(dao

專2)-2a3+12a2-18a=-2a(屬a2-6a+9)=-2a (a-3)2;(3)a2-2ab+b2-1=(a-b)2-1=(a-b+1)(a-b-1);(4)a2(x-y)-4b2(x-y)=(x-y)(a2-4b2)=(x-y) (a+2b)(a-2b);(5)(x+2)(x-6)+16=x2-4x+4=(x-2)2.

3樓:科比ai打鐵

(zhi1)ax2-16ay2=a(daox+4y)(內容x-4y);

(2)-2a3+12a2-18a

=-2a(a2-6a+9)

=-2a (a-3)2;

(3)a2-2ab+b2-1

=(a-b)2-1

=(a-b+1)(a-b-1);

(4)a2(x-y)-4b2(x-y)

=(x-y)(a2-4b2)

=(x-y) (a+2b)(a-2b);

(5)(x+2)(x-6)+16=x2-4x+4=(x-2)2.

把下列各式分解因式:(1)a2(x-y)2+2a(x-y)3+(x-y)4(2)(x2+y2)2-4x2y2

4樓:匿名使用者

(1)a2(x-y)2+2a(x-y)3+(x-y)4,=(x-y)2[a2+2a(x-y)+(x-y)2,=(x-y)2(a+x-y)2;

(2)(x2+y2)2-4x2y2,

=(x2+2xy+y2)(x2-2xy+y2),=(x+y)2(x-y)2.

把下列各式分解因式.(1)9a2-14b2(3)12a2?ab+12b2(3)a2-2ab-4+b2(4)x(x2+1)2-4x3(5)x2-7x-8

5樓:匿名使用者

(1)9a2-1

4b2=(3a+1

2b)(3a-1

2b);

(3)12a

?ab+12b

=12(a2-2ab+b2)=1

2(a-b)2;

(3)a2-2ab-4+b2=(a-b)2-4=(a-b+2)(a-b-2);

(4)x(x2+1)2-4x3=x[(x2+1)2-4x2]=x(x2+1+2x)(x2+1-2x)=x(x+1)2(x-1)2;

(5)x2-7x-8=(x-8)(x+1);

(6)x(x-y)2+y(y-x)=(x-y)[x(x-y)-y]=(x-y)(x2-xy-y).

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